A(5,3 ), B (11,-5) and P(12, y) are the vertices of a right triangle, right angled at P, then y ?
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Answer:
If A(5,3) ,B(11,-55) and P(12,y) are the vertices of a right angled triangle,then
AB
2
=
(11−5)
2
+(−5−3)
2
=10
BC
2
=
(11−12)
2
+(−5−y)
2
=
1+(−5−y)
2
AB
2
=100BC
2
=1+(−5−y)
2
AC
2
=(5−12)
2
+(3−y)
2
=49+(3−y)
2
AB
2
=AC
2
+BC
2
100=1+(+5+y)
2
+49+(3−y)
2
⟹100=1+25+10y+y
2
+49+3−6y+y
2
⟹2y
2
−4y=16
∴y=−2,4
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