Chemistry, asked by sanvi01vyas, 3 months ago

A 5.4-V battery is connected to a bulb whose resistance is 3.1Ω. What is the current through the bulb?​


mozammil921: dekhna bhai nhi hoga
Anonymous: inbox ke liye aap kise ke profile mein jao fllw ke side mein inbox ka option h
mozammil921: haan haan bhai ek baar aap try kijie
mozammil921: hii bhejie
mozammil921: nhi hoga shayad
Anonymous: o bhai
Anonymous: really nhi hota ha
mozammil921: Questions ki limit increase ho gyi hai shayad
mozammil921: dekha bhai
mozammil921: mera toh dimag kharab ho gya ye dekh kr

Answers

Answered by nikkiaadi
1

Answer:

Given:-

☛Voltage of battery = 5.4 V

☛Resistance = 3.1Ω

Find:-

☛Current produces-?

Solution:-

☛According to ohm's law,

\boxed{\bf{V=IR}}

V=IR

where,

v= voltage

I= current

R= Resistance

Put values,

\sf{\implies 5.4 = I \times 3.1 }⟹5.4=I×3.1

\sf{\implies I= \dfrac{5.4}{3.1}}⟹I=

3.1

5.4

\sf{ \implies I= 1.74}⟹I=1.74

Therefore , Current Produces through bulb is 1.74 A.

(Unit of Current = ampere (A)

Similar questions