A 5.82g silver coin is dissolved in nitric acid .when sodium chloride is added to the solution all the silver is prespitaed as Agcl The Agcl precipite weidhts 7.2g determine the persentage of silver in the coin
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Fraction of Ag in Ag Cl = 107.9/143.3 = 0.753 weight of Ag in 7.20 g Ag Cl
= 0.753 × 7.20 g = 5.42 g Ag
Hence the 5.82 g coin contains 5.42 g Ag = 0
Fraction of Ag in coin = 5.42 g/5.82 g
= 0.931 = 93.1 % Ag
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