a. 5. A child pulls a sled up a snow-covered hill. The child does 405 J of work on the sled. If the child walks 15 m up the hill, how large of a force must the child exert?
b.6. How much work is done on a small car if a 3150 N force is exerted to move it
75.5 m to the side of the road?
Answers
Answer:
(a) The force must be 27 Newton.
(b) The work done on the small car is 2.3×10⁵Joules.
Explanation:
First, let's see the relationship between force and work done which is given as;
(1)
Where,
W=work done on the body
F=force acting on the body
x=distance through which the body is displaced
CASE (a): Work done=405Joules
The work done by the child is(W) =405 Joules
The distance covered by the child in walking up the hill(x)=15 m
Inserting the values of "W" and "x" in equation (1) we get;
(2)
The force must be 27 Newton.
CASE (b): The force exerted is =3150N
The force exerted on the car=3150N
The distance required to move(x)=75.5m
Inserting the values of "F" and "x" in equation (1) we get;
The work done on the small car is 2.3×10⁵Joules.
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Answer:
The force exerted by by the child is 27 Newton.
The work done by small car is 2.3x 10^5.
Explanation:
Concept: Work done = Force x displacement
W = F. x
Where , W is the work done
F is the force acting
x is the displacement
Case (a)
Given: Work done = 405 J
Displacement= 15 m
Find: Force(F) exerted by child.
Step by step explanation
Work done = Force x displacement
W = F. x
405J = F x 15
Force(F) = 405/15
Force (F) = 27 Newton
The force exerted by by the child is 27 Newton.
Case (b)
Given: Force (F) = 3150 N
Displacement (x) = 75.5m
Find: Work done on small car.
Step by step explanation
Work done = Force x displacement
W = F. x
W= 3150x 75.5
W= 237825J
W= 2.3x 10^5
Hence , the work done by small car is 2.3x 10^5.
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