Question

A 5 ampere current is passed through a solution of zinc sulphate for 40 minutes. The amount of zinc deposited at the cathode is

Answer 1

We begin by calculating the charge .

Charge = It

Where :

I = The current in Amperes

t = Time in seconds

Time in seconds is given by :

40 × 60 = 2400 seconds

The charge is = 2400 × 5 = 12000 Coulombs

96500 coulombs --------> 1 mole

2 moles of electrons give one mole of Zinc.

Therefore :

1 mole = 96500 × 2 = 193000 Coulombs

The moles deposited by 12000 coulombs

The moles of zinc deposited is :

12000/193000 = 0.06218 moles

Molar mass of Zinc = 65 g

Amount of Zinc deposited t the cathode is :

= 65 × 0.06218 = 4.042 g

Answer 2

Answer:

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