A 5 coulomb charge experiences a force of 2000 Newton when moved between two points separated by a distance of 2centimetres in a uniform electric field the potential difference between the two points is options : (a)8v, (b)200v, (c )800v, (d)20000v
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We know that work done= force x displacement.
then work done = 2000 x 0.02= 40J
And potential difference = work done/charge
Therefore, V= 40/5 =8v.
Hope this helps you.
then work done = 2000 x 0.02= 40J
And potential difference = work done/charge
Therefore, V= 40/5 =8v.
Hope this helps you.
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