Question

A 5 digit number divisible by 3 is to be formed using the numbers 0 1 2 3 4 and 5 without repetition. The total number of ways this can be done is

Answer 1

Answer:

Step-by-step explanation:A number is divisible by 3 if the sum of the digits of the number is divisible by 3 . So from 1 ,2 , 3 , 4,5 we get -

0,1,2,4,5 and 1,2,3,4,5  

Where the sum of the 5 digits is divisible by 3.

Now let's take 0,1,2,4,5 first .

For the first place we have 4 numbers (0 excluded) ,for the second place we have 4 (now 0 included) ,for third 3 ,for fourth 2 and for fifth 1. Hence the number of choices we have is 4×4×3×2×1=96 .

Now we take 1,2,3,4,5

Here the number of choices we have is 5×4×3×2×1=120

Hence in total we have 120 +96 = 216 choices