Question

A 5 μF Capacitor Is Charged With Battery 100V. Find The Energy Stored.​

Answer 1

Explanation:

plzz see this attachment

Answer 2

Actually welcome to the Concept of the Capacitors and it's Energy

The Energy stored in Capacitors is given as,

E = 1/2 CV^2

Now here, we are given with

C = 5 × 10^-6 F

V = 100 V

so we get energy as

E = 1/2 ×5 × (100)^2 × 10^-6

E = 1/2 × 5 × 10^-2

E = 2.5 × 10^-2

E = 0.025 J