Question

A 5 kg ball is thrown upwards with the speed of 10 m/s. (take g=10 m/s^2)

(a) Calculate the maximum height attained by it.

(b) Find the potential energy when it reaches the highest point.

Answer 1

(b)At the highest point ball momentarily cones to rest. Therefpre, at the highest point velocity (v) is zero. 

Using equation: 

v^2 - u^2 = -2gS 

u^2 / 2g = S 

S = (10)^2 / 2 x 10 

S = 100 / 20 

S = 5 m 

Therefore, body reaches a maximum height of S = 5 m 

At this point Potential Energy (U) of particle is: 

U = mgS 

U = 5 x 10 x 5 

U = 250 J 


Here, I took g = 10 m/s^2 

If you take g = 9.8 m/s^2 you Kay get slightly different answer.

Answer 2

Answer:

5and 250

Explanation:

See the attachment below