Physics, asked by Rik2006ggn, 7 months ago

A 5 kg rifle fires a 10g bullet at a velocity of 500m/s find the recoil velocity of the rifle?

Answers

Answered by sucharithaa
1

Answer:

Explanation:

From conservation of momentum

Initial momentum=Final momentum

0=1/100kg*500m/s+5kg*v

-5kgm/s=5kg*v

v=-1m/s

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Answered by TheValkyrie
4

Answer:

\bigstar{\bold{Recoil\:velocity\:=\:-1\:m/s}}

Explanation:

\Large{\underline{\underline{\bf{Given:}}}}

  • Mass of rifle (m₁) = 5 kg
  • Mass of bullet (m₂) = 10 g =0.01 kg
  • Velocity of bullet (v₂) = 500m/s

\Large{\underline{\underline{\bf{To\:Find:}}}}

  • Recoil velocity of rifle (v₁)

\Large{\underline{\underline{\bf{Solution:}}}}

→ Recoil velocity of rifle is given by the equation

  v₁ = -m₂v₂/m₁

→ Substituting the given datas, we get

  v₁ = -0.01×500/5

  \boxed{\bold{Recoil\:velocity\:= -1\:m/s}}

→ Recoil velocity of gun is negative since it is in the direction opposite to that of motion of the bullet.

\Large{\underline{\underline{\bf{Notes:}}}}

  • Remember to convert all the given datas to the SI units before calculating.
  • Momentum before collission is equal to the momentum after collission in an isolated system.
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