Question

A 5 litre jug contains 4 litres of a saltwater solution that is 15 percent salt. if 1.5 litres of the solution spilts out of jug, and the jug is then filled to capacity with water, approximately what percent of the resulting solution in the jug is salt?

Answer 1

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Answer 2

Total quantity of (salt + water) solution = 4 litre       ( given)

the solution contains 15 % salt .

amount of salt in the solution at the beginning = $\frac{15}{100}$ × 4

                                                                            = $\frac{3}{20}$ ×4 = $\frac{12}{20}$ = $\frac{3}{5}$

                                                                                 =0.6 ltrs of salt

Rest is water = (4 - 0.6 )=3.4 ltrs of water.

1.5 litres of the solution spilts out of jug,

That means in 1.5 ltrs of a saltwater solution the portion of salt =( that is 15 % salt contain )=$\frac{15}{100}$ × 1.5 = $\frac{3}{20}$ ×$\frac{15}{10}$ = $\frac{3}{20}$ ×$\frac{3}{2}$ = $\frac{9}{40}$

                                                          =0.225 ltrs of salt by 1.5 ltrs of water

Salt in 4 ltrs a saltwater in resulting solution =0.6–0.225=0.375 ltrs

Hence quantity of water = 0.225+3.400=3.3625 ltrs

Percentage of salt in resulting solution of 4 ltrs =  $\frac{.375}{4}$ ×100

                                                                               = $\frac{375}{4000}$ × 100

                                                                                = $\frac{375}{40}$

                                                                                = 9.375%

Ans:-Approximately 9.375% of the resulting solution in the jug is salt.