A girl of height 90cm is walking away from the base of a lamp post at a speed of 1.2m/sec. if the lamp is 3.6m above the ground then find the length of her shadow after 4 seconds.
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Answer:
Let DE be x metres
BD=1.2*4=4.8
In ∆ABE and ∆CDE,
Angle B=angle D ( each is 90)
Angle E=angle E (common)
∆ABE~∆CDE (by AA similarity)
BE/DE=AB/CD
4.8+x/x=3.6/0.9
3x=4.8. (X=1.6)
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