Chemistry, asked by sanjaikumar8673, 1 year ago

A 5 m solution of h2so4 is diluted from 1 litre to avolume of 100 litres the normality of tha solution will be

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Answered by Anonymous
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Change in molarity after dilution: M1V1 = M2V2 5 x 1 L = M2 x 100 L M2 = 5 x (1 /100) = 0.05 M Now, Normality = n x Molarity N = 2 x 0.05 = 0.1 N.

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