a 5 metre long ladder is placed leaning towards a vertical walls is that it reaches the wall at a point of 4 m high if the foot of the ladder is moved on 6 metres towards the wall and find the distance by which the top of the ladder full slider word on the wall
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Hey there,
[tex]AC = 5m AB = 4m In the triangle ABC, using the Pythagoras theorem BC = \sqrt{AC^2 - AB^2 = \sqrt{25 - 16 = \sqrt{9 = 3m. BD = 3 - 1.6 = 1.4m. DE = 5m. EB = \sqrt{DE^2 - BD^2 = \sqrt{25 - 1.96 = \sqrt{23.04 = 4.8m. Ladder slides by the distance = 4.8m - 4 = 0.8m [/tex]
Hope this helps!
[tex]AC = 5m AB = 4m In the triangle ABC, using the Pythagoras theorem BC = \sqrt{AC^2 - AB^2 = \sqrt{25 - 16 = \sqrt{9 = 3m. BD = 3 - 1.6 = 1.4m. DE = 5m. EB = \sqrt{DE^2 - BD^2 = \sqrt{25 - 1.96 = \sqrt{23.04 = 4.8m. Ladder slides by the distance = 4.8m - 4 = 0.8m [/tex]
Hope this helps!
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