Question

A 5 V battery is connected across a resistor. If the current passing through the circuit is 5 mA, find the value of resistance.

Answer 1

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QUESTION -

A 5 V battery is connected across a resistor. If the current passing through the circuit is 5 mA, find the value of resistance...

SOLUTION -

From the question, we can derive the following information .....

A 5 V battery is connected across a resistor. If the current passing through the circuit is 5 mA.

This can be simply solved by using the Ohm ' s law.

Ohm ' s Law -

V = I R

Where :

V is the voltage in the circuit.

I is the current flowing in the circuit.

R is the resistance in the circuit.

Substuting the required values :

5 V = 5 mA × R

1 milli ampere is 0.001 A.

=> R = 1 / 1 m A => 1000 Ohm.

So the value of the resistance is 1000 Ohm.

ANSWER :

So the value of the resistance is 1000 Ohm.

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Resistance=1000\Omega}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Current(I) = 5 \: mA\\ \\ \tt: \implies Potential \: difference(V) = 5 \: V\\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Resistance(R) = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies V= IR\\ \\ \tt: \implies 5 = 0.005 \times R\\ \\ \tt: \implies R = \frac{5}{0.005} \\ \\ \green{\tt: \implies R = 1000\Omega} \\ \\ \blue{ \bold{Some \: related \: formula}} \\ \\ \red{\tt \circ \: Resistance \: in \: parallel} \\ \orange{ \tt \circ \: \frac{1}{ R_{equivalent} } = \frac{1}{ R_{1} } + \frac{1}{ R_{2} } + \frac{1}{ R_{3} } +....... + \frac{1}{ R_{n} } } \\ \\ \red{\tt \circ \: Resistance \: in \:series} \\ \orange{ \tt \circ \:{ R_{equivalent} } = { R_{1} } + { R_{2} } + { R_{3} } +....... + { R_{n} } }$