Question

a 50 cm silver bar shortens by 1.0 mm when cooled.how much was it cooled?

Answer 1

∆L=L*Alpha*∆T

∆L =change in linear length (10^-3 m)
L= Initial Length (0.5 m)
Alpha=coefficient of linear thermal expansion(given below)
∆T = change in temperature(To Find)

material: Silver
alpha = (19 to 19.7)*10^-6

substitute the following the data in the above equation to get the answer