a 50 cm silver bar shortens by 1.0 mm when cooled.how much was it cooled?
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∆L=L*Alpha*∆T
∆L =change in linear length (10^-3 m)
L= Initial Length (0.5 m)
Alpha=coefficient of linear thermal expansion(given below)
∆T = change in temperature(To Find)
material: Silver
alpha = (19 to 19.7)*10^-6
substitute the following the data in the above equation to get the answer
∆L =change in linear length (10^-3 m)
L= Initial Length (0.5 m)
Alpha=coefficient of linear thermal expansion(given below)
∆T = change in temperature(To Find)
material: Silver
alpha = (19 to 19.7)*10^-6
substitute the following the data in the above equation to get the answer
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