A 50 g bullet is fired from a 10 kg gun with a speed of 500 m/s.What is the speed of recoil of the gun?
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QUESTION ----- A 50 g bullet is fired from a 10 kg gun with a speed of 500 m/s.What is the speed of recoil of the gun?
ANSWER
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Momentum = Mass × Velocity
Momentum of Bullet = 50/1000 × 500
Momentum of Bullet = 25 kgm/s
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Let the velocity with which gun moves after recoil be x
Momentum = 10 × x
Momentum = 10x kgm/s
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According to Law of Conservation of Momentum,
Initial Momentum = Final Momentum
=> 25 kgm/s = 10x kgm/s
=> x = 25 / 10
=> x = 2.5 m/sec
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ANSWER :
SPEED OF RECOIL = 2.5 m/sec
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ANSWER
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Momentum = Mass × Velocity
Momentum of Bullet = 50/1000 × 500
Momentum of Bullet = 25 kgm/s
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Let the velocity with which gun moves after recoil be x
Momentum = 10 × x
Momentum = 10x kgm/s
____________________________
According to Law of Conservation of Momentum,
Initial Momentum = Final Momentum
=> 25 kgm/s = 10x kgm/s
=> x = 25 / 10
=> x = 2.5 m/sec
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ANSWER :
SPEED OF RECOIL = 2.5 m/sec
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