A 50 gm bullet moving with a velocity of 10 m/s gets
embedded into a 950 gm stationary body. The loss
in kinetic energy of the system will be-
(1) 5% (2) 50% (3) 100% (4) 95%
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Velocity of the bullet will be 0 at the end. Therefore, K.E will be 0. So, loss in K.E will be 100%
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