A 50 kg man standing on the surface of negligible friction kicks forward a 0.1kg stone so that it acquires a speed of 10 ms .Then the velocity acquired by the man is
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use m1v1=m2v2
50 x v1 = 0.1 x 10
v1 = 0.02
50 x v1 = 0.1 x 10
v1 = 0.02
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