A 50 kg sphere is projected vertically up with a speed of 200ms. It rises to a height of 1500m. The energy used up in overcoming friction is
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H = v^2/(2g) = 400/(2*9.81)=20.387 m.
But it has risen upto 12 m only.
An energy equivalent to mg(20.387 -12) is lost.
5*9.81 *8.387= 411.382J of energy is lost
But it has risen upto 12 m only.
An energy equivalent to mg(20.387 -12) is lost.
5*9.81 *8.387= 411.382J of energy is lost
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