Question

a) 500 students are asked to stand in rows and columns for a PT drill. Is it possible to
make them stand in such a way that there are an equal number of rows and
columns? If not, how many children will be left out in this arrangement?​

Answer 1

Step-by-step explanation:

Here, Number of children 500o

By getting the square root of this

number, we get,

In each row, the number of

children is 22.

And left out children are 16.

Answer 2

LET ME EXPLAIN IT TO YOU MATE!!!!!

SEE MATE,HERE WE HAVE BEEN GIVEN THAT THERE ARE 500 STUDENTS,AND ALL ARE TO BE ARRANGED IN SUCH A MAANER SO THAT NO.OF ROWS=NO.OF COLUMNS

WE KNOW,

WHERE NO. OF ROWS IS EQUAL TO NO. OF COLUMNS,THEN THE PRODUCT OF NO. OF ROWS AND NO. OF COLUMNS IS A PERFECT SQUARE...

THEREFORE,LET US FIND IF 500 IS A PERFECT SQUARE...

FOR THAT,WE HAVE TO FIND THE SQUARE ROOT OF 500.

$\sqrt{500} = 22.3606798$

THEREFORE, NO. OF STUDENTS CAN'T BE IN DECIMAL.... HENCE WE WILL FIND A PERFECT SQUARE NEAREST TO 500.

IN THE SERIES, WE FIND THAT 484 IS A PERFECT SQUARE NEAREST TO 500.

THEREFORE, 500-484=16

HENCE 16 STUDENTS WILL BE LEFT IN THE ARRANGEMENT.

NOW, LET'S PROCEED FURTHER....

$\sqrt{484} = 22$

THEREFORE,

${22}^{2} = 484$

HENCE, WE FOUND THAT THE SUITABLE NO. OF STUDENTS IS 22,SO THAT NO. OF ROWS=NO. OF COLUMNS.... AND 16 STUDENTS WILL BE LEFT IN THIS ARRANGEMENT....

HOPE YOU ARE REALLY HELPED MATE, PLEASE CONSIDER MARKING MY ANSWER AS BRAINLIEST.....