Question

a 500 Watt 220 volt bulb is supplied with 110 volt power consumption by the bulb will be​

Answer 1

Answer:

P=500W

V=220V

R=V*V/P = 220*220/500=96.8ohm

If

V=110V

P= V*V/R= 110*110/96.8= 125 W

Answer 2

The power consumption by the bulb will be 125 W.

Explanation:

It is given that,

Power of the bulb, P = 500 W

Voltage, V = 220 V

Let R is the resistance of the bulb. Power of an electrical appliances is given by :

$P=\dfrac{V^2}{R}$

$R=\dfrac{V^2}{P}$

$R=\dfrac{(220)^2}{500}$

R = 96.8 ohms

If voltage is, V' = 110 V

Again using formula of power as ,

$P'=\dfrac{V'^2}{R}$

$P'=\dfrac{(110)^2}{96.8}$

P' = 125 W

So, the power consumption by the bulb will be 125 W. Hence, this is the required solution.

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Electrical equipment

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