Question

A 500kg vehicle moving with a speed of of 10m/s brought to rest at a distance of 50m. (1) find the acceleration and time.

Answer 1

$<h2> hey DUDE </h2>$
given :-

mass of the vehicle = 500kg

v = 0

u = 10m/s

s = 50m

by third equation of motion, we get

→ 2as = v² - u²

→ 2 × a × 50 = 0 - 10²

→ 100a = -100

→ a = -100/100

→ a = -1 …(1)

we also know that a = (v - u)/t …(2)

by equation (1) and (2)

=> -1 = (0 - 10)/t

=> -1t = -10

=> t = -10/-1

=> t = 10

heny, acceleration is -1m/s^2 and time is 10 seconds

Answer 2

V= u+at and here m= 500kg
u = 10mper sec
v= 0
s= 50m
we know by Newton law of motion v= u+at 0=10+at
from here a= -10/t
s=ut+1/2 at^2
50=10t -5t
50=5t so t = 10sec and a = -1m per sec ^2