A 50N force is acting normally on an area of 10m2. Then the same force acts on half of this area. Calculate the pressure in each case and also find the relation between the two pressures
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F = 50N
A1 = 10m^2
A2 = 5m^2
P1 = F / A1 = 50 / 10 = 5N/m^2
When it acts on half of the area.
P2 = F / A2 = 50 / 5 = 10N/m^2
Relation between two pressures are
P2 = 2P1
Thanks
A1 = 10m^2
A2 = 5m^2
P1 = F / A1 = 50 / 10 = 5N/m^2
When it acts on half of the area.
P2 = F / A2 = 50 / 5 = 10N/m^2
Relation between two pressures are
P2 = 2P1
Thanks
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