Question

A 50ohm load dissipates 200 W. how much is the voltage and current across the load​

Answer 1

$\large \underline \bold{Question :-}$

$\star$ A 50 ohm load dissipates 200 W. how much is the voltage and current across the load ?

$\large \underline \bold{Answer :-}$

$\: \: \: \:$Voltage = 100 volt

$\: \: \: \:$Current = 2 ampere

$\large \underline \bold{Given :-}$

$\: \: \: \:$ resistance (R) = 50 ohm

$\: \: \: \: \: \:$ power (P) = 200 Watt

$\large \underline \bold{Usable \: Formula :-}$

$\: \: \: \:$$P =\dfrac{v^{2}}{R}$

$\: \: \: \:$$I =\dfrac{V}{R}$

$\large \underline \bold{Solution :-}$

Firstly -

$\: \: \: \: \: \:$$\sf{V^{2} = PR}$

$\: \: \: \: \: \:$$V =\sqrt{PR}$

$\: \: \: \: \: \:$$V =\sqrt{200\times 50}$

$\: \: \: \: \: \:$$V =\sqrt{(100\times 2)\times 50}$

$\: \: \: \: \: \:$$V =\sqrt{(100\times 100)}$

$\: \: \: \: \: \:$$V =\sqrt{(100)^{2}}$

$\: \: \: \: \: \:$$V = 100 \: volt$

Now ,

$\: \: \: \: \: \:$$\sf{I =\dfrac{V}{R}}$

$\: \: \: \: \: \:$$I =\dfrac{100}{50}$

$\: \: \: \: \: \:$$I = 2 \: ampere$

Answer 2

Answer:

1=2 ampre this is your answer