CBSE BOARD X, asked by pragya2785, 1 year ago

A 52 year old nearsighted person wears a glass with the power of minus 5.5 diopters for his distance viewing his doctors prescribe a correction of + 1.5 diopters in the near vision for his bifocals . this is measured relative to the main part of the lens .
what is the focal length of his distance viewing part of the lens ?
what is the focal lens office near vision section of the lens ?


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Answers

Answered by abir1201
6

Distance viewing:-

P = 1/f

Therefore, f = 1/P

So, f = 1/-5.5 = -0.45m


Near vision:-

P = 1/f

Therefore, f= 1/P

So, f = 1/1.5 = 0.67m


HOPE THIS HELPS!


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abir1201: You are in 10? CBSE?
Answered by rishabhyadav1172
2
answer is 0.67 I hope help u
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