Question

A 55 kg man holds a weight of 20 kg on his head. What is the work done by him against gravity if he moves a
distance of 20 m (i) on a horizontal road, (ii) on an
incline of 1 in 5? Take g = 10 ms 2.​

Answer 1

Answer:

Here, m= 55+20= 75 kg

       s=  20 m.

(1) Work done on a horizontal road:-

     W= Fs cosθ= Fs cos900= 0    (as θ=900)

(2) Work done on an incline :-

     Given sinθ= 

W= Fs cosθ= (mgsinθ)s cos00

     = 75 x 10 x 

x 20 x 1

W= 3000J

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