Question

a - 5b = 10, 5a + 3b = 17 elimination method​

Answer 1

Answer:

a=65/28

b=-43/28

Step-by-step explanation:

Let equation (1)

a-5b=10

let equation (2)

5a+3b=17

Now multiply equation (1) by 5 then you will get equation (3)

5a-25b=50

now substract equation (3) from (2) and you will get

28b=-43

=>b=-43/28

now substitute this value of b in equation (1) and you will get

a=10+5b

=>a=10+5×(-43/28)

=>a=65/28

Answer 2

$a=\dfrac{115}{28}$ and b = $\dfrac{-33}{28}$

Step-by-step explanation:

The given equations are:

a - 5b = 10                        ............. (1)

and  5a + 3b = 17             ............. (2)

To find, the values of a and b = ?

By Elimination method​,

From equation (1), we get

a = 5b + 10    

Put a = 5b + 10 in equation (2), we get    

5(5b + 10) + 3b = 17

⇒ 25b + 50 + 3b = 17

⇒ 28b  = 17 - 50

⇒ 28b  = - 33

⇒ b = $\dfrac{-33}{28}$

Put b = $\dfrac{-33}{28}$ in equation (1), we get

$a - 5(\dfrac{-33}{28} ) = 10$

⇒ $a+\dfrac{165}{28}= 10$

⇒ $a= 10-\dfrac{165}{28}=\dfrac{280-165}{28}$

⇒ $a=\dfrac{115}{28}$

∴ $a=\dfrac{115}{28}$ and b = $\dfrac{-33}{28}$