A 5cm tall object is placed at a distance of 20cm and focal length 30cm.Find position and nature of image formed by concave lens.Just tell the ans
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1/v - 1/(-20 )=1/(-30)
1/v=-1/20-1/30
=-50/20×30
v =-60/5=-12cm
so virtual and diminished at 12 cm
size=5×12/20=3cm
brainly6060:
got it
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