Question

A 5g piece of ice at -20 deg C is put into 10g water at 30 deg C. Assuming that the heat exchange is only between the water and ice, find the final temperature of the mixture [10]. Specific heat capacity of ice and water are respectively 2100 J Kg^-1 C^-1 and 4200 J Kg^-1 C^-1, while the latent heat of fusion of ice is 3:36x10^5 J Kg^-1.

Answer 1

Answer:

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Answer 2

Answer:

The water and ice coexist at   $0^{0} C$ because ice cannot be melted completely.

Explanation:

Given that:

A 5g piece of ice at -20 deg C is put into 10g water at 30 deg C

Specific heat capacity of ice : 2100 J $kg\^{-1} C^{-1}$

Specific heat capacity of  water: 4200 J $kg\^{-1} C^{-1}$

Solution:

Heat exchange is done between the ice and water.

Specific capacity of water = 4200 J $kg\^{-1} C^{-1}$

10 Kg of water is at 30 deg c

Therefore,

Heat gives by water(30 C) = 0.01 × 4200 × 30

                                           = 1260 J

Heat gives by water at $30^{0} C$ is 1260 J

Specific heat capacity of ice = 2100 J $kg\^{-1} C^{-1}$

Heat required to bring the ice to $0^{0} C$

⇒ 0.005 × 2100 × 20

⇒ 210 J

Heat required to melt ice = 0.005 × 3.36 × $10^{5}$

                                          = 1680 J

Heat gives by ice is 1680J

Hence we can note that whole ice cannot be melted.

Final answer:

As a result water and ice coexist at $0^{0} C$

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