Question

A 5kg ball is thrown upwards with a speed of 10m/s find potential energy when it reaches the maximum point and calculate the height attainedby it

Answer 1

At the highest point ball momentarily cones to rest. Therefpre, at the highest point velocity (v) is zero.

Using equation:

v^2 - u^2 = -2gS

u^2 / 2g = S

S = (10)^2 / 2 x 10

S = 100 / 20

S = 5 m

Therefore, body reaches a maximum height of S = 5 m

At this point Potential Energy (U) of particle is:

U = mgS

U = 5 x 10 x 5

U = 250 J


Here, I took g = 10 m/s^2

If you take g = 9.8 m/s^2 you Kay get slightly different answer.

Answer 2

Here,mass of ball,m = 5 kg
speed of ball,v = 10m/s

kinetic energy of ball, E=1/2m^2 =1/2×5×10=250j