A 5kg box is pushed with a force of 50N. The block accelerates at 8m/s/s. What is the coefficient of friction between the box and the surface? (use g=10m/s/s)
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Answer:
We know frictional force f=μN where N=normal force=mg
Given sliding frictionμ=0.25
Thus, f=0.25×50×10=125N
Hence F
net
=F
app
−f=575−125=450N
Also we know ForceF=ma
a=
50
450
=9m/s
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0.2
use free body diagram and calculate frictional force and then equate it with umg.
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