A 5kg mass moves under the influence of a force F vector=(4t^2icap-3tjcap)N,where t is the time in seconds. It starts at rest from the origin at t=0, its velocity and position at a later time t=1 second is
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Answer:
The work done by the force
F
=(3t
i
^
+5
j
^
) is
W=∫
F
.d
s
=∫(3t
i
^
+5
j
^
).(4tdt
i
^
)
=∫
0
2
12t
2
dt=
3
12[t
3
]
0
2
=
3
12(8−0)
=32 J
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