A 5kg rifle fires a 10g bullet at a velocity of 500 m s find the recoil velocity of the rifle
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Answer:
1 m/s
For Explanation refer to the image
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Given:
m1 = 5 kg
m2 = 10g = 0.01kg (g = 10, by formula g/100 i.e 10/100 = 0.01kg)
v2 = 500 m/s
To Find:
v1 = ?
Formula To Be Used:
m1v1 = m2v2 (by momentum conversion)
Procedure:
⇒m1v1 = m2v2
⇒5v1 = 0.01x500
⇒5v1 = 5
⇒v1 = 5/5
⇒v1 = 1 m/s
∴ The velocity of the rifle will be 1 m/s.
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