A 5m long ladder is leaning place during towards a vertical wall suchthat it reaches the wall at a point4m high. If the foot of the ladder is moved 1.6m towards the wall then find the distance by which thetop of the ladder would slide upwards on the wall.
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Answered by
121
Given:
Hypotneuse = 5 m
Base = ?
altitude = 4 m
Base² = hyp² - alt²
b² = 5² - 4²
b² = 25 - 16
b = √9
b = 3 m
When base is reduced by 1.6 m
Base = 3 - 1.6 = 1.4 m
hypotneuse = height of ladder = 5 m
altitude = ?
alt² = hyp²- base²
alt² = 5² - 1.4²
alt² = 25 - 1.96
alt = √23.04
alt = 4.8 m
Hypotneuse = 5 m
Base = ?
altitude = 4 m
Base² = hyp² - alt²
b² = 5² - 4²
b² = 25 - 16
b = √9
b = 3 m
When base is reduced by 1.6 m
Base = 3 - 1.6 = 1.4 m
hypotneuse = height of ladder = 5 m
altitude = ?
alt² = hyp²- base²
alt² = 5² - 1.4²
alt² = 25 - 1.96
alt = √23.04
alt = 4.8 m
Fawzan10:
Hope this helps you...
Answered by
70
Step-by-step explanation:
Let AC be the ladder of length 5 m and BC = 4 m be the height of the wall, which ladder is placed. If the foot of the ladder is moved 1.6 m towards the wall i.e, AD = 1.6 m, then the ladder is slide upward i.e. ,CE = x m.
In right angled ΔABC,
((((see the image)))))
which i give of these portion
In these portion you should write which i give in the image
Hence, the top of the ladder would slide upwards on the wall at distance 0.8 m.
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