how many consecutive natural numbers from 1 should be added to get 465
Answers
Answer:
1+2+3+...+n = n*(n+1)/2
where n is an integer and n+%3E=+1
Set this expression equal to 465 and solve
n(n+1)/2 = 465
n(n+1) = 2*465
n(n+1) = 930
n^2+n = 930
n^2+n-930 = 0
(n-30)(n+31) = 0
n-30 = 0 or n+31 = 0
n = 30 or n = -31
Since n+%3E=+1, then n = 30 is the only practical solution.
This means that the sum of the first 30 consecutive positive integers is equal to 465.
So,
1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+21+22+23+24+25+26+27+28+29+30 = 465
natural numbers are rhe numbers that start with the number 1....so, in the question that is asked how many natural consecutive odd nubers required to get 465....ao we should add 30 consecutive numbers to get 465....like(1,2)+(2,3)+(4,5)+(6,7)......so on....
Please mark as BRAINLIEST