A 5M solution of H2SO4 is diluted from 1 litre to a volume of 100litres the normality of solution will be
Answers
Answered by
305
Known:
M₁=5M
a₁=H₂SO₄⇒H₂ =2
V₁=1 L
V₂=1000 L
Asked: N₂?
Answer:
Use dilution formula:
M₁.a₁.V₁=M₂.a₂.V₂
and
Remember that the normality of formula: N=M.a
So ,
5.2.1=100.N
10 =100N
10 = N
100
0,1 =N
So,the normality is 0,1 N.
#Adam
M₁=5M
a₁=H₂SO₄⇒H₂ =2
V₁=1 L
V₂=1000 L
Asked: N₂?
Answer:
Use dilution formula:
M₁.a₁.V₁=M₂.a₂.V₂
and
Remember that the normality of formula: N=M.a
So ,
5.2.1=100.N
10 =100N
10 = N
100
0,1 =N
So,the normality is 0,1 N.
#Adam
Answered by
110
Given - M1 - 5M , V1 - 1L
M2-? , V2- 100L , n-factor (H2SO4) = 2
Solution - M1*V1 = M2*V2
5*1 = M2*100
M2 = 5/100 = 0.05
Normality = n-factor * Molarity
N = 2*0.05 = 0.01N
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