Question

A 5M solution of H2SO4 is diluted from 1 litre to a volume of 100litres the normality of solution will be

Answer 1

Known:
M₁=5M
a₁=H₂SO₄⇒H₂ =2
V₁=1 L
V₂=1000 L
Asked: N₂?
Answer:

Use dilution formula:
M₁.a₁.V₁=M₂.a₂.V₂
and
Remember that the normality of formula: N=M.a
So ,
5.2.1=100.N 
  10   =100N
  10   = N
 100
  0,1  =N

So,the normality is 0,1 N.

#Adam

Answer 2

Given - M1 - 5M , V1 - 1L

M2-? , V2- 100L , n-factor (H2SO4) = 2

Solution - M1*V1 = M2*V2

5*1 = M2*100

M2 = 5/100 = 0.05

Normality = n-factor * Molarity

N = 2*0.05 = 0.01N