a 5m60cm high vertical pole casts a shadow of 3m20cm long, the length cast by another pole is 10m50cm long what is the size of the other vertical pole
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Let x m be the length of the pole whose shadow is of length 10m50cm.
Let y m be the length of the pole whose shadow is 5m long.
Clearly, it is a case of direct variation.
i)
3.20
5.60
=
x
10.50
x=
5.60
10.50×3.20
=6
Hence, the length of the shadow is 6m.
ii)
3.20
5.60
=
5
y
x=
3.20
5.60×5
=8.75
Hence, the length of the pole is 8.75 meter
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