a 5v batteey of negligible internal resistance is connected across a 200 v battery and resistance of 39 ohm find the value of the current
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current=v/r
v =200+5=205
r= 39 ohm
205/39= 5.25 ampere
v =200+5=205
r= 39 ohm
205/39= 5.25 ampere
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