a= 6-√35, find a²+1/a²
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Answer:A=6-_/35
1/a=1/(6-_/35)=(6+_/35)(6^2-35)=6+_/35 (rationalised the denominator)
So, a^2+1/a^2=(6-_/35)^2(6+_/35)^2
=36+35-12_/35 +36+35+12_/35
=71+71=142...
Step-by-step explanation:
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