Question

A 6.90 m solution of koh in water contains 30% by mass of koh. What is density of solution in gm/ml.

Answer 1

Answer:

Hope it helps!!!

Plz! Mark me as brainliest ......

and don't forget to follow me ....✌

Answer 2

$\fbox{\texttt{\green{Answer:}}}$

Density of the solution = $\bold{1.288\:g\:mL^{-1}}$

$\fbox{\texttt{\pink{Given:}}}$

6.90 M KOH solution means that 6.90 moles of KOH are present in 1 litre of the solution.

Molar mass of KOH = $\bold{56\:g\:mol^{-1}}$

$\fbox{\texttt{\blue{To\:find:}}}$

Density of the KOH solution.

$\fbox{\texttt{\red{How\:to\:Find\::}}}$

We know that 6.90 moles of KOH are present in 1 litre of the solution.

But, 6.90 moles of KOH = 6.90 × 56 = 386.4 g

Thus, volume of solution containing 386.4 g KOH = 1000 mL

$\hrulefill$

30% by mass of KOH solution means that 30 g of KOH are present in 100 g of the solution.

$\therefore$ Mass of solution containing 386.4 g KOH = $\bold{\frac{100}{30}\times{}386.4\:g=1288\:g}$

$\therefore$ Density of solution = $\bold{\frac{Mass}{Volume}=\frac{1288\:g}{1000\:mL}=1.288\:g\:mL^{-1}}$