Question

when the pressure of 5 litre of N2 is doubled and its temperature is raised from 300 Kelvin to 600 Kelvin the final volume of the gas would be

Answer 1

According to me volume remains unchanged.

Answer 2

Let initial pressure = P
initial volume = 5 L
initial temperature = 300K

Final pressure = 2P
final temperature = 600K
final volume = V

From ideal gas law, PV = nRT, we get

PV/T = nR = constant. So

$\frac{P_f V_f}{T_f} = \frac{P_i V_i}{T_i} \\ \\ \frac{2P \times V}{600} = \frac{P \times 5}{300} \\ \\ V = \frac{P \times 5}{300} \times \frac{600}{2P} \\ \\ V = 5 \: litres$


Thus, final volume is 5 litres.