if tana=3 then find sina +cosa-1/sina-cosa+1
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The answer is given below :
Given,
tanA = 3,
So, cosA = 1/√10
=> 1/cosA = √10
Now,
sinA + cosA - 1
--------------------
sinA - cosA + 1
dividing both the numerator and the denominator by cosA, we get :
tanA + 1 - (1/cosA)
= ------------------------
tanA - 1 + (1/cosA)
3 + 1 - √10
= --------------
3 - 1 + √10
4 - √10
= ----------
2 + √10
Thank you for your question.
Given,
tanA = 3,
So, cosA = 1/√10
=> 1/cosA = √10
Now,
sinA + cosA - 1
--------------------
sinA - cosA + 1
dividing both the numerator and the denominator by cosA, we get :
tanA + 1 - (1/cosA)
= ------------------------
tanA - 1 + (1/cosA)
3 + 1 - √10
= --------------
3 - 1 + √10
4 - √10
= ----------
2 + √10
Thank you for your question.
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