a = 6, b = 3, c = -3, d = 10 find
the value of the algebra sum
2a+4b-3c
Answers
Answered by
0
33 is the answer
- a=6 so 2a= 2*6=12
- b=3 so 4b=4*3=12
- c=(-3) so -3c= (-3)*(-3)=9
- so 2a+4b-3c=12+12+9 = 33
Answered by
1
Answer:
33
Step-by-step explanation:
2x6+4x3-3x-3
12+12+9
24+9
33
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