Question

A 6 kg balls strike a verticle wall with a velocity 34m/s and rebounds with a velocity of 26m/s the impulse is

Answer 1

Answer:

48 N - sec

Explanation:

Given :

Mass of ball is 6 kg

Initial velocity ( u ) = 34 m / sec

Final velocity ( v ) = 26 m /sec

We know :

Impulse = Force × Time

I = F × t

I = m ( v - u ) / t × t  [ F = m a & a = v - u / t ]

I = m ( v - u )

Now putting values here we get :

I =  6 × ( 34 - 26 ) N - sec

I = 6 × 8 N - sec

I = 48 N - sec

Thus the impulse is 48 N - sec .

Answer 2

Answer:

${\bold{\therefore Impulse=48\:N-s}}$

Explanation:

${\bold{\huge{\underline{SOLUTION-}}}}$

• In the given question information given about a 6 kg ball that strikes a vertical wall with velocity of 34 m/s and then rebounds with another velocity of 26 m/s.

• We have to find Impusle.

$\underline \bold{Given : } \\ \\ \implies Mass \: of \: ball = 6 \: kg \\ \\ \implies Initial \:velocity(u) = 34 \: m/s \\ \\ \implies Final \: velocity (v)= 26 \: m/s \\ \\ \underline \bold{To \: Find : } \\ \\ \implies Impulse = ?$

• According to given question :

$\bold{According\:to\:Impulse\:formula:}\\\\\implies I= F\times T\\\\\bold{I= impulse}\\\bold{F= force}\\\bold{T= time}\\\\\implies I= F\times T-----(1)\\\\\bold{Using\:formula\: of \: force:}\\\\\implies F=Ma\\\\\implies F=M(\frac{v - u}{T}) -----(2)\\\\\bold{Putting\:value\:of\:F\:in\:(1)}\\\\\implies I=M\times\frac{(v - u)}{T}\times T\\\\\implies I=M\times(v - u)\\\\\implies I=6\times(34 - 26)\\\\\implies I=6\times8\\\\\bold{\implies I= 48\:N-s}$

${\bold{\therefore Impulse=48\:N-s}}$