Question

A 6 m wide path runs outside and around the circular flower garden whose diameter is 70 m. Find the area of the path ( π=22/7 or 3.14).​

Answer 1

Step-by-step explanation:

$\huge \tt{\text{A} \blue{N} \orange{S} \pink{W} \green{E} \red{R}} :) :)$

Radius of the park =r

Circumference of the park =2πr

176=2πr

$= > \frac{70}{2\pi}\\= > r= \frac{70}{2 \times \frac{22}{7} } \\ = > r= \frac{70 \times 6}{2 \times 22}\\ = > r= \huge\tt \blue{9.5454m}$

$\tt{Area \: of \: road =π(9.54+6{)}^{2} −π(9.54{)}^{2}</strong><strong>}</strong><strong>\\ =π(91.24−285.77) \\= \frac{22}{7} (6−9.54)(9.54+2)\\= \frac{22}{7} ×6×83.0116\\\huge \tt \pink{=158.62  {m}^{2} }$

Hope it helpful...☃️

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Ignore <P> signs....

Answer 2

Answer:

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Step-by-step explanation:

circumference of ground = 2πr = 220m

radius of ground = 220/2πr = 110/π = 35

area of ground = πr^2 = 22/7 x 35 x 35

A = 110 x 110 x 7/22 = 3850m^2

radius of ground - Garden path = 35-7 = 28m

Area = 22/7 x 28 x 28 = 88 x 28 = 2464m^2

area of path = 3850 - 2464 = 1386m^2