A 6 micro Farad is raised in PD from 10to20 V compute increase in potential energy
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Electrical potential energy stored in capacitor is CV²/2.
Increase in energy, ΔU = C(V’² - V²)
Putting C = 6 micro farad ( 6 ×10^-6),
V'=20 V and V= 10 V, we can get the answer.
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