Question

A 6 ohm resistance wire is doubled on itself. Calculate the new resistance of the wire

Answer 1

Answer:

24 ohm

Explanation:

New length ľ = 2l.

Since ,volume(length × area) remains same, Area becomes half.

 = A/2.

So, new resistance = p × ľ/Â = 4 × p × l/A = 24

Regards

kshitij

Answer 2

Resistance=ρL/A

Here, Resistance= 6ohm

Therefore,6=ρL/A

In second case

Resistance,R'=ρL'/A'

As the wire is doubled so L'=L/2, A'=2A

So new resistance,

R'=ρL/4A=(1/4)ρL/A

But ρL/A=6 So, R'=6/4=1.5Ω

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