Question

find the zeros of the polynomial root2x^2-3x-2root2​

Answer 1

Answer:

-1/2...........................................

Answer 2

Answer:

$\large\boxed{\sf{\sqrt{2}\:\:and\;\;\dfrac{1}{\sqrt{2}}}}$

Step-by-step explanation:

Given quadratic Polynomial

$\sqrt{2} {x}^{2} - 3x - 2 \sqrt{2}$

To find the roots

$\sqrt{2} {x}^{2} - 3x - 2 \sqrt{2} = 0 \\ \\ = > \sqrt{2} {x}^{2} - 4x + x - 2 \sqrt{2} = 0 \\ \\ = > \sqrt{2} x(x - \sqrt{2} ) + 1( - 2 \sqrt{2} ) = 0 \\ \\ = > (x - \sqrt{2} )( \sqrt{2} x + 1) = 0 \\ \\ = > x - \sqrt{2} = 0 \: \: \: and \: \: \: \: \sqrt{2} x + 1 = 0 \\ \\ = > x = \sqrt{2} \: \: \: \: and \: \: \: \: x = - \frac{1}{ \sqrt{2} }$

Hence the roots are √2 and 1/√2