A 6 Ω resistance wire is doubled up by folding
Calculate the new resistance of the wire ?
class 10 [ cbse ]
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area get doubled and length get reduced to half
R1/R2=(L1/L2)×(a2/a1)
R1/R2={L1/(L1/2)}×{(2*a1)/a1}
6/R2={2}×{2}
R2=6/4
R1/R2=(L1/L2)×(a2/a1)
R1/R2={L1/(L1/2)}×{(2*a1)/a1}
6/R2={2}×{2}
R2=6/4
Anonymous:
i removed the pic
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